Basic Trig Ratios FunctionDefinitionMnemonicsinθ\sin\thetasinθOppositeHypotenuse\dfrac{\text{Opposite}}{\text{Hypotenuse}}HypotenuseOppositeSOHcosθ\cos\thetacosθAdjacentHypotenuse\dfrac{\text{Adjacent}}{\text{Hypotenuse}}HypotenuseAdjacentCAHtanθ\tan\thetatanθOppositeAdjacent\dfrac{\text{Opposite}}{\text{Adjacent}}AdjacentOppositeTOAcscθ\csc\thetacscθHypotenuseOpposite=1sinθ\dfrac{\text{Hypotenuse}}{\text{Opposite}} = \dfrac{1}{\sin\theta}OppositeHypotenuse=sinθ1Reciprocal of sinsecθ\sec\thetasecθHypotenuseAdjacent=1cosθ\dfrac{\text{Hypotenuse}}{\text{Adjacent}} = \dfrac{1}{\cos\theta}AdjacentHypotenuse=cosθ1Reciprocal of coscotθ\cot\thetacotθAdjacentOpposite=1tanθ\dfrac{\text{Adjacent}}{\text{Opposite}} = \dfrac{1}{\tan\theta}OppositeAdjacent=tanθ1Reciprocal of tan Pythagorean Identities IdentityDerived FormDerived Formsin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1sin2θ+cos2θ=1sin2θ=1−cos2θ\sin^2\theta = 1 - \cos^2\thetasin2θ=1−cos2θcos2θ=1−sin2θ\cos^2\theta = 1 - \sin^2\thetacos2θ=1−sin2θtan2θ+1=sec2θ\tan^2\theta + 1 = \sec^2\thetatan2θ+1=sec2θtan2θ=sec2θ−1\tan^2\theta = \sec^2\theta - 1tan2θ=sec2θ−1sec2θ−tan2θ=1\sec^2\theta - \tan^2\theta = 1sec2θ−tan2θ=11+cot2θ=csc2θ1 + \cot^2\theta = \csc^2\theta1+cot2θ=csc2θcot2θ=csc2θ−1\cot^2\theta = \csc^2\theta - 1cot2θ=csc2θ−1csc2θ−cot2θ=1\csc^2\theta - \cot^2\theta = 1csc2θ−cot2θ=1 Reciprocal Identities IdentityEquivalentcscθ=1sinθ\csc\theta = \dfrac{1}{\sin\theta}cscθ=sinθ1sinθ=1cscθ\sin\theta = \dfrac{1}{\csc\theta}sinθ=cscθ1secθ=1cosθ\sec\theta = \dfrac{1}{\cos\theta}secθ=cosθ1cosθ=1secθ\cos\theta = \dfrac{1}{\sec\theta}cosθ=secθ1cotθ=1tanθ\cot\theta = \dfrac{1}{\tan\theta}cotθ=tanθ1tanθ=1cotθ\tan\theta = \dfrac{1}{\cot\theta}tanθ=cotθ1 Quotient Identities Identitytanθ=sinθcosθ\tan\theta = \dfrac{\sin\theta}{\cos\theta}tanθ=cosθsinθcotθ=cosθsinθ\cot\theta = \dfrac{\cos\theta}{\sin\theta}cotθ=sinθcosθ Co-function Identities IdentityIdentitysinθ=cos(90°−θ)\sin\theta = \cos(90° - \theta)sinθ=cos(90°−θ)cosθ=sin(90°−θ)\cos\theta = \sin(90° - \theta)cosθ=sin(90°−θ)tanθ=cot(90°−θ)\tan\theta = \cot(90° - \theta)tanθ=cot(90°−θ)cotθ=tan(90°−θ)\cot\theta = \tan(90° - \theta)cotθ=tan(90°−θ)secθ=csc(90°−θ)\sec\theta = \csc(90° - \theta)secθ=csc(90°−θ)cscθ=sec(90°−θ)\csc\theta = \sec(90° - \theta)cscθ=sec(90°−θ) Even/Odd Identities FunctionIdentityTypesin(−θ)\sin(-\theta)sin(−θ)=−sinθ= -\sin\theta=−sinθOddcos(−θ)\cos(-\theta)cos(−θ)=cosθ= \cos\theta=cosθEventan(−θ)\tan(-\theta)tan(−θ)=−tanθ= -\tan\theta=−tanθOddcsc(−θ)\csc(-\theta)csc(−θ)=−cscθ= -\csc\theta=−cscθOddsec(−θ)\sec(-\theta)sec(−θ)=secθ= \sec\theta=secθEvencot(−θ)\cot(-\theta)cot(−θ)=−cotθ= -\cot\theta=−cotθOdd Sum and Difference Formulas Formulasin(A+B)=sinAcosB+cosAsinB\sin(A + B) = \sin A\cos B + \cos A\sin Bsin(A+B)=sinAcosB+cosAsinBsin(A−B)=sinAcosB−cosAsinB\sin(A - B) = \sin A\cos B - \cos A\sin Bsin(A−B)=sinAcosB−cosAsinBcos(A+B)=cosAcosB−sinAsinB\cos(A + B) = \cos A\cos B - \sin A\sin Bcos(A+B)=cosAcosB−sinAsinBcos(A−B)=cosAcosB+sinAsinB\cos(A - B) = \cos A\cos B + \sin A\sin Bcos(A−B)=cosAcosB+sinAsinBtan(A+B)=tanA+tanB1−tanAtanB\tan(A + B) = \dfrac{\tan A + \tan B}{1 - \tan A\tan B}tan(A+B)=1−tanAtanBtanA+tanBtan(A−B)=tanA−tanB1+tanAtanB\tan(A - B) = \dfrac{\tan A - \tan B}{1 + \tan A\tan B}tan(A−B)=1+tanAtanBtanA−tanB Double-Angle Formulas FormulaAlternate Formssin(2θ)=2sinθcosθ\sin(2\theta) = 2\sin\theta\cos\thetasin(2θ)=2sinθcosθcos(2θ)=cos2θ−sin2θ\cos(2\theta) = \cos^2\theta - \sin^2\thetacos(2θ)=cos2θ−sin2θ=2cos2θ−1=1−2sin2θ= 2\cos^2\theta - 1 = 1 - 2\sin^2\theta=2cos2θ−1=1−2sin2θtan(2θ)=2tanθ1−tan2θ\tan(2\theta) = \dfrac{2\tan\theta}{1 - \tan^2\theta}tan(2θ)=1−tan2θ2tanθ Half-Angle Formulas Formulasin (θ2)=±1−cosθ2\sin\!\left(\dfrac{\theta}{2}\right) = \pm\sqrt{\dfrac{1 - \cos\theta}{2}}sin(2θ)=±21−cosθcos (θ2)=±1+cosθ2\cos\!\left(\dfrac{\theta}{2}\right) = \pm\sqrt{\dfrac{1 + \cos\theta}{2}}cos(2θ)=±21+cosθtan (θ2)=±1−cosθ1+cosθ=sinθ1+cosθ=1−cosθsinθ\tan\!\left(\dfrac{\theta}{2}\right) = \pm\sqrt{\dfrac{1 - \cos\theta}{1 + \cos\theta}} = \dfrac{\sin\theta}{1 + \cos\theta} = \dfrac{1 - \cos\theta}{\sin\theta}tan(2θ)=±1+cosθ1−cosθ=1+cosθsinθ=sinθ1−cosθ The sign of the half-angle formulas depends on the quadrant of θ2\dfrac{\theta}{2}2θ. Power-Reducing Formulas Formulasin2θ=1−cos(2θ)2\sin^2\theta = \dfrac{1 - \cos(2\theta)}{2}sin2θ=21−cos(2θ)cos2θ=1+cos(2θ)2\cos^2\theta = \dfrac{1 + \cos(2\theta)}{2}cos2θ=21+cos(2θ)tan2θ=1−cos(2θ)1+cos(2θ)\tan^2\theta = \dfrac{1 - \cos(2\theta)}{1 + \cos(2\theta)}tan2θ=1+cos(2θ)1−cos(2θ) Product-to-Sum Formulas FormulasinAcosB=12[sin(A+B)+sin(A−B)]\sin A\cos B = \dfrac{1}{2}[\sin(A + B) + \sin(A - B)]sinAcosB=21[sin(A+B)+sin(A−B)]cosAcosB=12[cos(A−B)+cos(A+B)]\cos A\cos B = \dfrac{1}{2}[\cos(A - B) + \cos(A + B)]cosAcosB=21[cos(A−B)+cos(A+B)]sinAsinB=12[cos(A−B)−cos(A+B)]\sin A\sin B = \dfrac{1}{2}[\cos(A - B) - \cos(A + B)]sinAsinB=21[cos(A−B)−cos(A+B)] Law of Sines and Cosines FormulaUseasinA=bsinB=csinC\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}sinAa=sinBb=sinCcTwo angles and a side, or two sides and an angle opposite onec2=a2+b2−2abcosCc^2 = a^2 + b^2 - 2ab\cos Cc2=a2+b2−2abcosCTwo sides and included angle, or three sidesArea=12absinC\text{Area} = \dfrac{1}{2}ab\sin CArea=21absinCTwo sides and included angle Special Angle Values Anglesin\sinsincos\coscostan\tantan0°0°0°00011100030°30°30°12\dfrac{1}{2}2132\dfrac{\sqrt{3}}{2}2313=33\dfrac{1}{\sqrt{3}} = \dfrac{\sqrt{3}}{3}31=3345°45°45°22\dfrac{\sqrt{2}}{2}2222\dfrac{\sqrt{2}}{2}2211160°60°60°32\dfrac{\sqrt{3}}{2}2312\dfrac{1}{2}213\sqrt{3}390°90°90°111000undefined Degree-Radian Conversions DegreesRadians0°0°0°00030°30°30°π6\dfrac{\pi}{6}6π45°45°45°π4\dfrac{\pi}{4}4π60°60°60°π3\dfrac{\pi}{3}3π90°90°90°π2\dfrac{\pi}{2}2π120°120°120°2π3\dfrac{2\pi}{3}32π135°135°135°3π4\dfrac{3\pi}{4}43π150°150°150°5π6\dfrac{5\pi}{6}65π180°180°180°π\piπ270°270°270°3π2\dfrac{3\pi}{2}23π360°360°360°2π2\pi2π Conversion Formulas ConversionFormulaDegrees to radiansradians=degrees×π180\text{radians} = \text{degrees} \times \dfrac{\pi}{180}radians=degrees×180πRadians to degreesdegrees=radians×180π\text{degrees} = \text{radians} \times \dfrac{180}{\pi}degrees=radians×π180 Return to Trigonometry for the full topic list.