Geometry

Area of Basic Shapes

Last updated: March 2026 · Beginner
Before you start

You should be comfortable with:

Real-world applications
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Carpentry

Measurements, material estimation, cutting calculations

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Retail & Finance

Discounts, tax, tips, profit margins

Area is the amount of space inside a flat (two-dimensional) shape. While perimeter tells you the distance around a shape, area tells you how much surface it covers. Area is measured in square units — square feet (ft2\text{ft}^2), square inches (in2\text{in}^2), square meters (m2\text{m}^2), and so on.

Understanding area is essential for estimating materials — flooring, paint, sod, roofing, and fabric are all purchased based on area.

Area of a Rectangle

A rectangle with length ll and width ww has area:

A=l×wA = l \times w

Example 1: A room is 15 ft long and 12 ft wide. Find the area.

A=15×12=180 ft2A = 15 \times 12 = 180 \text{ ft}^2

Answer: The area is 180 square feet.

Area of a Square

A square is a rectangle where all sides are equal. With side length ss:

A=s2A = s^2

Example 2: A square patio tile is 18 inches on each side. Find its area.

A=182=324 in2A = 18^2 = 324 \text{ in}^2

Answer: The area is 324 square inches.

Area of a Triangle

A triangle with base bb and height hh (the perpendicular distance from the base to the opposite vertex) has area:

A=12bhA = \frac{1}{2}bh

The height must be perpendicular to the base — it forms a right angle with the base. The height is not necessarily a side of the triangle; it may be a line drawn inside or outside the triangle.

Example 3: A triangular piece of land has a base of 40 ft and a height of 25 ft. Find the area.

A=12(40)(25)=12(1000)=500 ft2A = \frac{1}{2}(40)(25) = \frac{1}{2}(1000) = 500 \text{ ft}^2

Answer: The area is 500 square feet.

Why does this formula work? A triangle is exactly half of a rectangle with the same base and height. If you duplicate a triangle and flip it, the two pieces form a rectangle with area b×hb \times h. Half of that is 12bh\frac{1}{2}bh.

Area of a Parallelogram

A parallelogram is a four-sided shape where opposite sides are parallel and equal. Its area uses the base bb and the perpendicular height hh (not the slanted side):

A=bhA = bh

Example 4: A parallelogram has a base of 10 m and a height of 6 m. Find the area.

A=10×6=60 m2A = 10 \times 6 = 60 \text{ m}^2

Answer: The area is 60 square meters.

Important: The slanted side of a parallelogram is not the height. The height is always the perpendicular distance between the base and the opposite side.

Area of a Trapezoid

A trapezoid has exactly one pair of parallel sides, called the bases (b1b_1 and b2b_2). The height hh is the perpendicular distance between the two bases.

A=12(b1+b2)×hA = \frac{1}{2}(b_1 + b_2) \times h

This formula averages the two bases and multiplies by the height.

Example 5: A trapezoid has bases of 8 in and 14 in, with a height of 5 in. Find the area.

A=12(8+14)(5)=12(22)(5)=12(110)=55 in2A = \frac{1}{2}(8 + 14)(5) = \frac{1}{2}(22)(5) = \frac{1}{2}(110) = 55 \text{ in}^2

Answer: The area is 55 square inches.

Area Formula Reference

ShapeFormulaVariables
RectangleA=lwA = lwll = length, ww = width
SquareA=s2A = s^2ss = side length
TriangleA=12bhA = \frac{1}{2}bhbb = base, hh = height
ParallelogramA=bhA = bhbb = base, hh = perpendicular height
TrapezoidA=12(b1+b2)hA = \frac{1}{2}(b_1 + b_2)hb1,b2b_1, b_2 = parallel bases, hh = height

Common Area Formulas

A = lwlwRectanglehbTriangleA = ½bhhbA = bhParallelogramhb₁b₂Trapezoid

Real-World Application: Carpentry — Estimating Flooring Materials

A homeowner wants to install hardwood flooring in an L-shaped living room. The room can be divided into two rectangles:

  • Rectangle 1: 20 ft by 14 ft
  • Rectangle 2: 10 ft by 8 ft

Flooring is sold by the square foot. How many square feet of flooring should be ordered?

Step 1: Find the area of each rectangle.

A1=20×14=280 ft2A_1 = 20 \times 14 = 280 \text{ ft}^2

A2=10×8=80 ft2A_2 = 10 \times 8 = 80 \text{ ft}^2

Step 2: Add the two areas.

Atotal=280+80=360 ft2A_{\text{total}} = 280 + 80 = 360 \text{ ft}^2

Step 3: Add 10% for waste from cuts, fitting, and defective pieces.

360×0.10=36 ft2360 \times 0.10 = 36 \text{ ft}^2

360+36=396 ft2360 + 36 = 396 \text{ ft}^2

Answer: The homeowner should order at least 396 square feet of flooring. Breaking irregular rooms into rectangles (or triangles) is the standard method for estimating area in construction. Always add a waste factor — 10% is typical for flooring, and more complex patterns may require 15%.

Composite Shapes

Real-world shapes are often combinations of basic shapes. To find the area of a composite shape:

  1. Break it into basic shapes (rectangles, triangles, etc.)
  2. Calculate each area separately
  3. Add the areas together (or subtract if a shape is cut out)

Example 6: A wall is 12 ft wide and 9 ft tall, with a triangular gable on top. The gable has a base of 12 ft and a height of 4 ft. Find the total area.

Rectangle (wall):

Arect=12×9=108 ft2A_{\text{rect}} = 12 \times 9 = 108 \text{ ft}^2

Triangle (gable):

Atri=12(12)(4)=24 ft2A_{\text{tri}} = \frac{1}{2}(12)(4) = 24 \text{ ft}^2

Total:

Atotal=108+24=132 ft2A_{\text{total}} = 108 + 24 = 132 \text{ ft}^2

Answer: The total area is 132 square feet.

Practice Problems

Test your understanding with these problems. Click to reveal each answer.

Problem 1: Find the area of a rectangle with length 25 ft and width 18 ft.

A=25×18=450 ft2A = 25 \times 18 = 450 \text{ ft}^2

Answer: 450 ft2450 \text{ ft}^2

Problem 2: A triangle has a base of 16 cm and a height of 9 cm. Find its area.

A=12(16)(9)=12(144)=72 cm2A = \frac{1}{2}(16)(9) = \frac{1}{2}(144) = 72 \text{ cm}^2

Answer: 72 cm272 \text{ cm}^2

Problem 3: A parallelogram has a base of 13 in and a height of 7 in. Find its area.

A=13×7=91 in2A = 13 \times 7 = 91 \text{ in}^2

Answer: 91 in291 \text{ in}^2

Problem 4: A trapezoid has bases of 10 m and 16 m, with a height of 8 m. Find its area.

A=12(10+16)(8)=12(26)(8)=104 m2A = \frac{1}{2}(10 + 16)(8) = \frac{1}{2}(26)(8) = 104 \text{ m}^2

Answer: 104 m2104 \text{ m}^2

Problem 5: A retail store floor is 50 ft by 30 ft. A 10 ft by 10 ft storage area in one corner will not be carpeted. How many square feet of carpet are needed?

Total floor area: 50×30=1500 ft250 \times 30 = 1500 \text{ ft}^2

Storage area: 10×10=100 ft210 \times 10 = 100 \text{ ft}^2

Carpet needed: 1500100=1400 ft21500 - 100 = 1400 \text{ ft}^2

Answer: 1400 ft21400 \text{ ft}^2 of carpet

Key Takeaways

  • Area measures the space inside a flat shape, in square units (ft2\text{ft}^2, m2\text{m}^2, etc.)
  • Rectangle: A=lwA = lw. Triangle: A=12bhA = \frac{1}{2}bh. Parallelogram: A=bhA = bh. Trapezoid: A=12(b1+b2)hA = \frac{1}{2}(b_1 + b_2)h
  • The height must always be perpendicular to the base — this is a common mistake to watch for
  • For composite shapes, break them into basic shapes, find each area, and add (or subtract) as needed
  • When ordering materials, always add a waste factor (typically 10%) on top of your calculated area

Return to Geometry for more topics in this section.

Last updated: March 28, 2026