Algebra

Multi-Step Equations

Last updated: March 2026 · Beginner
Before you start

You should be comfortable with:

Real-world applications
πŸ’Š
Nursing

Medication dosages, IV drip rates, vital monitoring

πŸ’°
Retail & Finance

Discounts, tax, tips, profit margins

Many real-world equations require more than one or two steps to solve. A multi-step equation is any linear equation where you must perform three or more operations β€” combining like terms, distributing, moving variables across the equals sign β€” before you arrive at the answer. Once you have the strategy down, even the longest-looking equations become routine.

The General Strategy

Follow this order every time:

  1. Simplify each side separately β€” distribute parentheses and combine like terms.
  2. Move variable terms to one side β€” add or subtract to collect all the variable terms together.
  3. Move constant terms to the other side β€” add or subtract to isolate the variable term.
  4. Divide (or multiply) to solve β€” get the variable alone with a coefficient of 1.

Think of it as tidying up, then isolating.

Combining Like Terms First

Sometimes the same side of an equation has multiple terms with the variable or multiple constant terms. Combine them before doing anything else.

Example 1: 3x+5+2xβˆ’1=243x + 5 + 2x - 1 = 24

Step 1 β€” Combine like terms on the left side:

The variable terms 3x3x and 2x2x combine to 5x5x. The constants 55 and βˆ’1-1 combine to 44.

5x+4=245x + 4 = 24

Step 2 β€” Subtract 4 from both sides:

5x=205x = 20

Step 3 β€” Divide both sides by 5:

x=4x = 4

Answer: x=4x = 4

Check: 3(4)+5+2(4)βˆ’1=12+5+8βˆ’1=243(4) + 5 + 2(4) - 1 = 12 + 5 + 8 - 1 = 24 . Correct.

Example 2: 7βˆ’2x+4x+3=187 - 2x + 4x + 3 = 18

Step 1 β€” Combine like terms on the left:

2x+10=182x + 10 = 18

Step 2 β€” Subtract 10:

2x=82x = 8

Step 3 β€” Divide by 2:

x=4x = 4

Answer: x=4x = 4

Using the Distributive Property

When parentheses appear, distribute the factor across every term inside before combining like terms.

Example 3: 4(2xβˆ’3)+5=214(2x - 3) + 5 = 21

Step 1 β€” Distribute the 4:

8xβˆ’12+5=218x - 12 + 5 = 21

Step 2 β€” Combine constants on the left (βˆ’12+5=βˆ’7-12 + 5 = -7):

8xβˆ’7=218x - 7 = 21

Step 3 β€” Add 7 to both sides:

8x=288x = 28

Step 4 β€” Divide by 8:

x=3.5x = 3.5

Answer: x=3.5x = 3.5

Check: 4(2(3.5)βˆ’3)+5=4(7βˆ’3)+5=4(4)+5=16+5=214(2(3.5) - 3) + 5 = 4(7 - 3) + 5 = 4(4) + 5 = 16 + 5 = 21 . Correct.

Example 4: βˆ’2(x+6)+3x=1-2(x + 6) + 3x = 1

Pay close attention to distributing the negative.

Step 1 β€” Distribute βˆ’2-2:

βˆ’2xβˆ’12+3x=1-2x - 12 + 3x = 1

Step 2 β€” Combine like terms (βˆ’2x+3x=x-2x + 3x = x):

xβˆ’12=1x - 12 = 1

Step 3 β€” Add 12:

x=13x = 13

Answer: x=13x = 13

Variables on Both Sides β€” Expanded Treatment

When the variable appears on both sides of the equation, you must move all variable terms to one side and all constants to the other. The key decision is which side to move the variables to β€” either side works, but choosing the side that keeps the variable coefficient positive avoids sign errors.

Example 5: 6x+4=2x+206x + 4 = 2x + 20

The variable appears on both sides. Since 6x6x is larger than 2x2x, keep the variable on the left.

Step 1 β€” Subtract 2x2x from both sides:

4x+4=204x + 4 = 20

Step 2 β€” Subtract 4 from both sides:

4x=164x = 16

Step 3 β€” Divide by 4:

x=4x = 4

Answer: x=4x = 4

Check: Left: 6(4)+4=286(4) + 4 = 28. Right: 2(4)+20=282(4) + 20 = 28 . Both sides equal 28.

Example 6: 3xβˆ’7=8x+183x - 7 = 8x + 18

Here 8x8x is the bigger variable term, so let’s move 3x3x to the right to keep the coefficient positive.

Step 1 β€” Subtract 3x3x from both sides:

βˆ’7=5x+18-7 = 5x + 18

Step 2 β€” Subtract 18 from both sides:

βˆ’25=5x-25 = 5x

Step 3 β€” Divide by 5:

x=βˆ’5x = -5

Answer: x=βˆ’5x = -5

Check: Left: 3(βˆ’5)βˆ’7=βˆ’15βˆ’7=βˆ’223(-5) - 7 = -15 - 7 = -22. Right: 8(βˆ’5)+18=βˆ’40+18=βˆ’228(-5) + 18 = -40 + 18 = -22 . Both sides equal βˆ’22-22.

Example 7: Distributive Property on Both Sides

Solve 5(x+1)=3(xβˆ’1)+125(x + 1) = 3(x - 1) + 12.

Step 1 β€” Distribute on both sides:

5x+5=3xβˆ’3+125x + 5 = 3x - 3 + 12

Step 2 β€” Combine constants on the right (βˆ’3+12=9-3 + 12 = 9):

5x+5=3x+95x + 5 = 3x + 9

Step 3 β€” Subtract 3x3x:

2x+5=92x + 5 = 9

Step 4 β€” Subtract 5:

2x=42x = 4

Step 5 β€” Divide by 2:

x=2x = 2

Answer: x=2x = 2

Special Cases: No Solution and Infinite Solutions

Not every multi-step equation has exactly one answer. There are two special outcomes to watch for.

No Solution (Contradiction)

If the variables cancel and you end up with a false statement, the equation has no solution.

Example: Solve 2(x+3)=2x+102(x + 3) = 2x + 10.

Distribute: 2x+6=2x+102x + 6 = 2x + 10

Subtract 2x2x: 6=106 = 10

This is false β€” no value of xx can make it true. No solution.

Infinite Solutions (Identity)

If the variables cancel and you get a true statement, every real number is a solution.

Example: Solve 3(xβˆ’1)=3xβˆ’33(x - 1) = 3x - 3.

Distribute: 3xβˆ’3=3xβˆ’33x - 3 = 3x - 3

Subtract 3x3x: βˆ’3=βˆ’3-3 = -3

This is always true. All real numbers are solutions.

Real-World Application: Retail β€” Comparing Phone Plans

A retail worker is helping a customer compare two phone plans:

  • Plan A: $25 per month plus $0.10 per text message
  • Plan B: $15 per month plus $0.20 per text message

At how many text messages per month do the two plans cost the same?

Let tt represent the number of text messages. Set the costs equal:

25+0.10t=15+0.20t25 + 0.10t = 15 + 0.20t

Step 1 β€” Subtract 0.10t0.10t from both sides:

25=15+0.10t25 = 15 + 0.10t

Step 2 β€” Subtract 15 from both sides:

10=0.10t10 = 0.10t

Step 3 β€” Divide by 0.10:

t=100t = 100

Answer: At 100 text messages, both plans cost the same ($35). Fewer than 100 texts makes Plan B cheaper; more than 100 makes Plan A cheaper.

Real-World Application: Nursing β€” IV Flow Rate Adjustment

A nurse is recalculating an IV drip. The original order delivers 80 mL per hour. A new medication requires adding 20 mL of solution every 2 hours on top of the base rate. The total volume to infuse in 6 hours is 540 mL.

80h+20h2=54080h + \frac{20h}{2} = 540

Simplify 20h2=10h\frac{20h}{2} = 10h:

80h+10h=54080h + 10h = 540

90h=54090h = 540

h=6h = 6

Answer: The 6-hour timeframe is confirmed. The combined rate is 90 mL per hour, which the nurse uses to set the infusion pump correctly.

Common Mistakes to Avoid

  1. Distributing to only part of the parentheses. In 4(2xβˆ’3)4(2x - 3), you must multiply 4 by both 2x2x and βˆ’3-3: the result is 8xβˆ’128x - 12, not 8xβˆ’38x - 3.
  2. Forgetting to distribute the negative sign. βˆ’2(x+6)=βˆ’2xβˆ’12-2(x + 6) = -2x - 12, not βˆ’2x+6-2x + 6.
  3. Moving a term without changing its sign. When you subtract 2x2x from both sides, 6x6x becomes 4x4x, not 8x8x.
  4. Stopping too early. If you have 3x=123x = 12, you still need to divide β€” the answer is x=4x = 4, not 3x=123x = 12.
  5. Not checking special cases. If all the variable terms cancel, determine whether the result is a contradiction (no solution) or an identity (infinite solutions).

Practice Problems

Test your understanding with these problems. Click to reveal each answer.

Problem 1: Solve 5x+3βˆ’2x=185x + 3 - 2x = 18

Combine like terms: 3x+3=183x + 3 = 18

Subtract 3: 3x=153x = 15

Divide by 3: x=5x = 5

Answer: x=5x = 5

Problem 2: Solve 3(x+4)βˆ’2=193(x + 4) - 2 = 19

Distribute: 3x+12βˆ’2=193x + 12 - 2 = 19

Combine: 3x+10=193x + 10 = 19

Subtract 10: 3x=93x = 9

Divide by 3: x=3x = 3

Answer: x=3x = 3

Problem 3: Solve 7xβˆ’5=3x+117x - 5 = 3x + 11

Subtract 3x3x: 4xβˆ’5=114x - 5 = 11

Add 5: 4x=164x = 16

Divide by 4: x=4x = 4

Check: 7(4)βˆ’5=237(4) - 5 = 23 and 3(4)+11=233(4) + 11 = 23 . Correct.

Answer: x=4x = 4

Problem 4: Solve 2(3xβˆ’1)=4(x+5)βˆ’82(3x - 1) = 4(x + 5) - 8

Distribute both sides: 6xβˆ’2=4x+20βˆ’86x - 2 = 4x + 20 - 8

Simplify right: 6xβˆ’2=4x+126x - 2 = 4x + 12

Subtract 4x4x: 2xβˆ’2=122x - 2 = 12

Add 2: 2x=142x = 14

Divide by 2: x=7x = 7

Check: 2(3(7)βˆ’1)=2(20)=402(3(7) - 1) = 2(20) = 40 and 4(7+5)βˆ’8=4(12)βˆ’8=48βˆ’8=404(7 + 5) - 8 = 4(12) - 8 = 48 - 8 = 40 . Correct.

Answer: x=7x = 7

Problem 5: Solve βˆ’3(2x+4)+10x=2x+8-3(2x + 4) + 10x = 2x + 8

Distribute: βˆ’6xβˆ’12+10x=2x+8-6x - 12 + 10x = 2x + 8

Combine left: 4xβˆ’12=2x+84x - 12 = 2x + 8

Subtract 2x2x: 2xβˆ’12=82x - 12 = 8

Add 12: 2x=202x = 20

Divide by 2: x=10x = 10

Check: βˆ’3(2(10)+4)+10(10)=βˆ’3(24)+100=βˆ’72+100=28-3(2(10) + 4) + 10(10) = -3(24) + 100 = -72 + 100 = 28 and 2(10)+8=282(10) + 8 = 28 . Correct.

Answer: x=10x = 10

Problem 6: Solve 4(x+2)=4x+94(x + 2) = 4x + 9

Distribute: 4x+8=4x+94x + 8 = 4x + 9

Subtract 4x4x: 8=98 = 9

This is false.

Answer: No solution.

Key Takeaways

  • Multi-step equations require simplifying each side first, then isolating the variable
  • Always distribute before combining like terms
  • When variables appear on both sides, move them to whichever side keeps the coefficient positive
  • Watch for special cases: a false statement means no solution; a true statement means infinite solutions
  • Distributing a negative sign is the most common source of errors β€” check it twice
  • Always verify your answer by substituting back into the original equation

Return to Algebra for more topics in this section.

Last updated: March 29, 2026