Trigonometry

The Unit Circle

Last updated: March 2026 · Intermediate
Before you start

You should be comfortable with:

Real-world applications
📐
Carpentry

Measurements, material estimation, cutting calculations

⚡
Electrical

Voltage drop, wire sizing, load balancing

The unit circle is a circle with a radius of 1, centered at the origin of a coordinate plane. It is the bridge between right-triangle trig and the broader world of trig functions — allowing you to define sine and cosine for any angle, not just angles in a right triangle.

What Is the Unit Circle?

Draw a circle on the xyxy-plane with center (0,0)(0, 0) and radius 1. Pick any point on the circle and draw a line from the origin to that point. The angle θ\theta is measured from the positive xx-axis, going counterclockwise.

The key insight: the coordinates of that point are (cos⁡θ,sin⁡θ)(\cos\theta, \sin\theta).

  • The xx-coordinate is cos⁡θ\cos\theta
  • The yy-coordinate is sin⁡θ\sin\theta

This works because if you drop a vertical line from the point to the xx-axis, you form a right triangle with hypotenuse 1 (the radius). Then cos⁡θ=adjacent1=x\cos\theta = \frac{\text{adjacent}}{1} = x and sin⁡θ=opposite1=y\sin\theta = \frac{\text{opposite}}{1} = y.

The Unit Circle with Key Points

xyQ IQ IIQ IIIQ IV(1, 0)0°(0, 1)90°(−1, 0)180°(0, −1)270°45°θ(0, 0)

The Four Quadrants

As the angle θ\theta increases from 0 to 360 degrees, the point moves counterclockwise around the circle, passing through four quadrants. The signs of sine and cosine change depending on which quadrant the angle is in.

QuadrantAngle Rangecos⁡θ\cos\theta (x)sin⁡θ\sin\theta (y)Both Positive?
I0° to 90°++++All positive
II90° to 180°−-++Sine positive
III180° to 270°−-−-None positive
IV270° to 360°++−-Cosine positive

The ASTC Rule (All Students Take Calculus)

A popular mnemonic for remembering the signs is All Students Take Calculus — or A S T C — starting in Quadrant I and going counterclockwise:

  • A (Quadrant I) — All trig functions are positive
  • S (Quadrant II) — only Sine is positive
  • T (Quadrant III) — only Tangent is positive
  • C (Quadrant IV) — only Cosine is positive

Since tan⁡θ=sin⁡θcos⁡θ\tan\theta = \frac{\sin\theta}{\cos\theta}, tangent is positive whenever sine and cosine have the same sign (both positive in Q I, both negative in Q III).

Key Coordinates on the Unit Circle

These four points are the starting foundation:

AngleCoordinates (cos⁡θ,sin⁡θ)(\cos\theta, \sin\theta)
0°(1,0)(1, 0)
90°(0,1)(0, 1)
180°(−1,0)(-1, 0)
270°(0,−1)(0, -1)
360°(1,0)(1, 0) — same as 0°

At these angles, either sine or cosine is 0 and the other is ±1\pm 1. You will learn the coordinates of the special angles (30°, 45°, 60°, etc.) in the Special Angles topic.

Connecting the Unit Circle to Right Triangles

For any angle θ\theta in Quadrant I, imagine the right triangle formed by:

  • The radius (from origin to the point on the circle) — this is the hypotenuse, with length 1
  • The horizontal distance from the origin to the point — this is cos⁡θ\cos\theta
  • The vertical distance from the xx-axis to the point — this is sin⁡θ\sin\theta

Since the hypotenuse is 1:

sin⁡θ=opposite1=opposite=y\sin\theta = \frac{\text{opposite}}{1} = \text{opposite} = y

cos⁡θ=adjacent1=adjacent=x\cos\theta = \frac{\text{adjacent}}{1} = \text{adjacent} = x

This is why sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1 — it is the Pythagorean theorem applied to a triangle with hypotenuse 1: x2+y2=12x^2 + y^2 = 1^2.

Worked Examples

Example 1: Determining the Sign

What is the sign of sin⁡(210°)\sin(210°)?

210 degrees is in Quadrant III (between 180° and 270°). In Q III, both sine and cosine are negative.

Answer: sin⁡(210°)\sin(210°) is negative.

Example 2: Finding Coordinates

A point on the unit circle is at angle θ=60°\theta = 60°. We know that sin⁡(60°)=32\sin(60°) = \frac{\sqrt{3}}{2} and cos⁡(60°)=12\cos(60°) = \frac{1}{2}. What are the coordinates?

The coordinates are (cos⁡60°,sin⁡60°)=(12,32)(\cos 60°, \sin 60°) = \left(\frac{1}{2}, \frac{\sqrt{3}}{2}\right).

Answer: The point is at (12,32)≈(0.5,0.866)\left(\frac{1}{2}, \frac{\sqrt{3}}{2}\right) \approx (0.5, 0.866).

Example 3: Using Symmetry

If cos⁡(50°)=0.6428\cos(50°) = 0.6428, what is cos⁡(310°)\cos(310°)?

310° is in Quadrant IV. The reference angle is 360°−310°=50°360° - 310° = 50°. In Q IV, cosine is positive.

cos⁡(310°)=cos⁡(50°)=0.6428\cos(310°) = \cos(50°) = 0.6428

Answer: cos⁡(310°)=0.6428\cos(310°) = 0.6428

Why the Unit Circle Matters

The unit circle extends trigonometry beyond right triangles. With right triangles, you can only handle acute angles (0° to 90°). The unit circle defines sine and cosine for any angle — 0° to 360° and beyond. This is essential for:

  • AC circuits — electricians analyze alternating current using sine waves that cycle through all four quadrants
  • Rotation and circular motion — describing positions on a wheel, gear, or orbit
  • Graphing trig functions — the sine and cosine graphs are generated by tracing the unit circle

Practice Problems

Test your understanding with these problems. Click to reveal each answer.

Problem 1: What is the sign of cos⁡(150°)\cos(150°)?

150° is in Quadrant II (between 90° and 180°). In Q II, cosine is negative (only sine is positive).

Answer: cos⁡(150°)\cos(150°) is negative.

Problem 2: In which quadrant is an angle if sin⁡θ>0\sin\theta > 0 and cos⁡θ<0\cos\theta < 0?

Sine is positive in Q I and Q II. Cosine is negative in Q II and Q III. The overlap is Quadrant II.

Answer: Quadrant II.

Problem 3: What are the coordinates of the point on the unit circle at 180°?

(cos⁡180°,sin⁡180°)=(−1,0)(\cos 180°, \sin 180°) = (-1, 0)

Answer: (−1,0)(-1, 0)

Problem 4: If sin⁡(40°)=0.6428\sin(40°) = 0.6428, what is sin⁡(140°)\sin(140°)?

140° is in Quadrant II. The reference angle is 180°−140°=40°180° - 140° = 40°. In Q II, sine is positive.

sin⁡(140°)=sin⁡(40°)=0.6428\sin(140°) = \sin(40°) = 0.6428

Answer: sin⁡(140°)=0.6428\sin(140°) = 0.6428

Problem 5: Why is tan⁡(90°)\tan(90°) undefined?

At 90°, the coordinates are (0,1)(0, 1). Tangent is sin⁡θcos⁡θ=10\frac{\sin\theta}{\cos\theta} = \frac{1}{0}, which is division by zero.

Answer: tan⁡(90°)\tan(90°) is undefined because cos⁡(90°)=0\cos(90°) = 0, and division by zero is undefined.

Key Takeaways

  • The unit circle is a circle with radius 1 centered at the origin
  • Any point on the unit circle has coordinates (cos⁡θ,sin⁡θ)(\cos\theta, \sin\theta)
  • ASTC tells you the signs: All (Q I), Sine (Q II), Tangent (Q III), Cosine (Q IV)
  • The identity sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1 comes directly from the Pythagorean theorem on the unit circle
  • The unit circle extends trig beyond right triangles, defining sine and cosine for all angles

Return to Trigonometry for more topics in this section.

Last updated: March 28, 2026