Pre Algebra

Cubes and Cube Roots

Last updated: March 2026 · Beginner
Before you start

You should be comfortable with:

Real-world applications
πŸ“
Carpentry

Measurements, material estimation, cutting calculations

🌑️
HVAC

Refrigerant charging, airflow, system sizing

A cube of a number is that number multiplied by itself three times. A cube root reverses the process β€” it asks, β€œWhat number, when cubed, gives this value?” Cubes and cube roots come up whenever you work with three-dimensional measurements like volume, and they have one key difference from square roots: cube roots of negative numbers exist.

What Is a Perfect Cube?

A perfect cube is the result of multiplying a whole number by itself three times.

n3=nΓ—nΓ—nn^3 = n \times n \times n

Here are the perfect cubes you should know:

nnn3n^3nnn3n^3
116216
287343
3278512
4649729
5125101,000

Example 1: Evaluate 434^3

43=4Γ—4Γ—4=16Γ—4=644^3 = 4 \times 4 \times 4 = 16 \times 4 = 64

Answer: 43=644^3 = 64

Example 2: Evaluate 636^3

63=6Γ—6Γ—6=36Γ—6=2166^3 = 6 \times 6 \times 6 = 36 \times 6 = 216

Answer: 63=2166^3 = 216

Cube Root Notation

The cube root of a number aa is written with a radical symbol and a small 3 (called the index):

a3=bmeansb3=a\sqrt[3]{a} = b \quad \text{means} \quad b^3 = a

We read a3\sqrt[3]{a} as β€œthe cube root of aa.”

Example 3: Evaluate 273\sqrt[3]{27}

We need a number that, when cubed, gives 27.

3Γ—3Γ—3=27β‡’273=33 \times 3 \times 3 = 27 \quad \Rightarrow \quad \sqrt[3]{27} = 3

Answer: 273=3\sqrt[3]{27} = 3

Example 4: Evaluate 1253\sqrt[3]{125}

5Γ—5Γ—5=125β‡’1253=55 \times 5 \times 5 = 125 \quad \Rightarrow \quad \sqrt[3]{125} = 5

Answer: 1253=5\sqrt[3]{125} = 5

Example 5: Evaluate 1,0003\sqrt[3]{1{,}000}

10Γ—10Γ—10=1,000β‡’1,0003=1010 \times 10 \times 10 = 1{,}000 \quad \Rightarrow \quad \sqrt[3]{1{,}000} = 10

Answer: 1,0003=10\sqrt[3]{1{,}000} = 10

Negative Cube Roots β€” They Exist!

Here is the big difference between square roots and cube roots. You cannot take the square root of a negative number (in real numbers), but you can take the cube root of a negative number.

Why? Because a negative number times a negative number times a negative number is negative:

(βˆ’3)Γ—(βˆ’3)Γ—(βˆ’3)=9Γ—(βˆ’3)=βˆ’27(-3) \times (-3) \times (-3) = 9 \times (-3) = -27

Therefore:

βˆ’273=βˆ’3\sqrt[3]{-27} = -3

This works for any negative perfect cube:

ValueCube Root
βˆ’1-1βˆ’1-1
βˆ’8-8βˆ’2-2
βˆ’27-27βˆ’3-3
βˆ’64-64βˆ’4-4
βˆ’125-125βˆ’5-5
βˆ’216-216βˆ’6-6

Example 6: Evaluate βˆ’643\sqrt[3]{-64}

(βˆ’4)3=(βˆ’4)Γ—(βˆ’4)Γ—(βˆ’4)=16Γ—(βˆ’4)=βˆ’64(-4)^3 = (-4) \times (-4) \times (-4) = 16 \times (-4) = -64

Answer: βˆ’643=βˆ’4\sqrt[3]{-64} = -4

Example 7: Evaluate βˆ’7293\sqrt[3]{-729}

(βˆ’9)3=(βˆ’9)Γ—(βˆ’9)Γ—(βˆ’9)=81Γ—(βˆ’9)=βˆ’729(-9)^3 = (-9) \times (-9) \times (-9) = 81 \times (-9) = -729

Answer: βˆ’7293=βˆ’9\sqrt[3]{-729} = -9

Why Square Roots of Negatives Fail but Cube Roots Succeed

It comes down to how many times you multiply:

  • Squaring (two factors): (βˆ’a)Γ—(βˆ’a)=+a2(-a) \times (-a) = +a^2. Two negatives always make a positive, so you can never square a real number and get a negative result. That is why βˆ’25\sqrt{-25} has no real answer.

  • Cubing (three factors): (βˆ’a)Γ—(βˆ’a)Γ—(βˆ’a)=+a2Γ—(βˆ’a)=βˆ’a3(-a) \times (-a) \times (-a) = +a^2 \times (-a) = -a^3. The third factor flips the sign back to negative. So every negative number has a real cube root.

The Volume Connection

Cubes and cube roots have a natural connection to volume. A cube with side length ss has volume:

V=s3V = s^3

If you know the volume and want the side length:

s=V3s = \sqrt[3]{V}

Example 8: Side Length from Volume

A shipping box has a volume of 343 cubic inches and is a perfect cube. What is the side length?

s=3433=7Β inchess = \sqrt[3]{343} = 7 \text{ inches}

Verification: 73=7Γ—7Γ—7=3437^3 = 7 \times 7 \times 7 = 343. Checks out.

Answer: Each side is 7 inches.

Estimating Non-Perfect Cube Roots

Just like with square roots, you can estimate cube roots of numbers that are not perfect cubes.

Example 9: Estimate 503\sqrt[3]{50}

Step 1: Find the surrounding perfect cubes.

33=27and43=643^3 = 27 \quad \text{and} \quad 4^3 = 64

So 503\sqrt[3]{50} is between 3 and 4.

Step 2: Determine where 50 falls between 27 and 64.

50βˆ’2764βˆ’27=2337β‰ˆ0.62\frac{50 - 27}{64 - 27} = \frac{23}{37} \approx 0.62

Step 3: Estimate.

503β‰ˆ3+0.62=3.62\sqrt[3]{50} \approx 3 + 0.62 = 3.62

Calculator check: 503β‰ˆ3.684\sqrt[3]{50} \approx 3.684. Our estimate is in the right ballpark (the linear interpolation is less accurate for cube roots, but it gives a reasonable starting point).

Real-World Application: Carpentry β€” Cubic Storage

A carpenter is building a cube-shaped storage bin that needs to hold 512 cubic feet of firewood. What should each side measure?

s=5123=8Β feets = \sqrt[3]{512} = 8 \text{ feet}

Verification: 8Γ—8Γ—8=5128 \times 8 \times 8 = 512. Checks out.

Answer: Each side should be 8 feet.

The carpenter also knows the total surface area will be:

SurfaceΒ Area=6Γ—s2=6Γ—64=384Β squareΒ feet\text{Surface Area} = 6 \times s^2 = 6 \times 64 = 384 \text{ square feet}

This helps estimate the lumber needed.

Real-World Application: HVAC β€” Duct Sizing

An HVAC technician needs to replace a circular duct with a square duct of equal cross-sectional area. If the target airflow requires a duct with a cross-section of 64 square inches, the side of the square duct is:

s=64=8Β inchess = \sqrt{64} = 8 \text{ inches}

But if the technician needs a cube-shaped plenum (junction box) with a volume of 216 cubic inches, the side length is:

s=2163=6Β inchess = \sqrt[3]{216} = 6 \text{ inches}

Understanding the difference between squares (for area) and cubes (for volume) is critical in the HVAC trade.

Comparing Squares vs. Cubes at a Glance

PropertySquaresCubes
Operationn2=nΓ—nn^2 = n \times nn3=nΓ—nΓ—nn^3 = n \times n \times n
Inversea\sqrt{a}a3\sqrt[3]{a}
Negative inputsNot realReal and negative
Geometric meaningArea of a squareVolume of a cube
Growth rateModerateFast

Common Mistakes to Avoid

  1. Assuming cube roots of negative numbers do not exist. They do. βˆ’83=βˆ’2\sqrt[3]{-8} = -2.

  2. Confusing cubes with multiplication by 3. 43=644^3 = 64, not 1212. Cubing means multiplying the number by itself three times, not multiplying by 3.

  3. Mixing up square root and cube root notation. 64=8\sqrt{64} = 8 (square root), but 643=4\sqrt[3]{64} = 4 (cube root). The little index number matters.

  4. Forgetting that cube growth is fast. 103=1,00010^3 = 1{,}000 while 102=10010^2 = 100. Volumes grow much faster than areas.

Practice Problems

Problem 1: Evaluate 535^3.

53=5Γ—5Γ—5=1255^3 = 5 \times 5 \times 5 = 125

Answer: 125125

Problem 2: Evaluate 5123\sqrt[3]{512}.

8Γ—8Γ—8=5128 \times 8 \times 8 = 512

Answer: 5123=8\sqrt[3]{512} = 8

Problem 3: Evaluate βˆ’1253\sqrt[3]{-125}.

(βˆ’5)Γ—(βˆ’5)Γ—(βˆ’5)=βˆ’125(-5) \times (-5) \times (-5) = -125

Answer: βˆ’1253=βˆ’5\sqrt[3]{-125} = -5

Problem 4: A cube has a volume of 729 cubic centimeters. What is the side length?

s=7293=9Β cms = \sqrt[3]{729} = 9 \text{ cm}

Verification: 93=7299^3 = 729. Checks out.

Answer: The side length is 9 cm.

Problem 5: Estimate 1003\sqrt[3]{100} without a calculator.

43=644^3 = 64 and 53=1255^3 = 125.

100βˆ’64125βˆ’64=3661β‰ˆ0.59\frac{100 - 64}{125 - 64} = \frac{36}{61} \approx 0.59

1003β‰ˆ4+0.59=4.59\sqrt[3]{100} \approx 4 + 0.59 = 4.59

(Calculator: 1003β‰ˆ4.642\sqrt[3]{100} \approx 4.642)

Answer: Approximately 4.594.59

Problem 6: Evaluate βˆ’1,0003\sqrt[3]{-1{,}000}.

(βˆ’10)3=(βˆ’10)Γ—(βˆ’10)Γ—(βˆ’10)=βˆ’1,000(-10)^3 = (-10) \times (-10) \times (-10) = -1{,}000

Answer: βˆ’1,0003=βˆ’10\sqrt[3]{-1{,}000} = -10

Key Takeaways

  • A perfect cube is n3=nΓ—nΓ—nn^3 = n \times n \times n. Memorize the cubes of 1 through 10.
  • The cube root a3\sqrt[3]{a} asks β€œwhat number cubed gives aa?”
  • Cube roots of negative numbers are real β€” unlike square roots. βˆ’83=βˆ’2\sqrt[3]{-8} = -2.
  • Cubes connect directly to volume: V=s3V = s^3 for a cube, and s=V3s = \sqrt[3]{V} to find the side.
  • Do not confuse cubing (n3n^3) with multiplying by 3 (3n3n).

Return to Pre-Algebra for more topics in this section.

Last updated: March 29, 2026