Pre Algebra

Integer Operations

Last updated: March 2026 · Beginner
Before you start

You should be comfortable with:

Real-world applications
🌡️
HVAC

Refrigerant charging, airflow, system sizing

Electrical

Voltage drop, wire sizing, load balancing

Up to this point, most of your math work has used positive numbers — counts, measurements, and prices that are always zero or above. But the real world has temperatures below zero, bank accounts overdrawn, elevations below sea level, and electrical charges that flow in opposite directions. Integers are the number set that includes positive numbers, negative numbers, and zero, giving you the language to describe all of these situations with a single system.

What Are Integers?

Integers are the set of whole numbers and their negatives:

, 3, 2, 1, 0, 1, 2, 3, \ldots,\ -3,\ -2,\ -1,\ 0,\ 1,\ 2,\ 3,\ \ldots

Key facts about integers:

  • Positive integers (1,2,3,1, 2, 3, \ldots) represent quantities above zero
  • Negative integers (1,2,3,-1, -2, -3, \ldots) represent quantities below zero
  • Zero (00) is an integer that is neither positive nor negative
  • Integers do not include fractions or decimals — 2.5-2.5 and 34\frac{3}{4} are not integers

On a number line, negative integers appear to the left of zero and positive integers appear to the right. The further left a number is, the smaller its value: 7<3<0<4<10-7 < -3 < 0 < 4 < 10.

Adding Integers

There are two cases to consider when adding integers.

Case 1: Same Sign

When both numbers have the same sign, add their absolute values and keep the common sign.

5+3=8(both positive, answer is positive)5 + 3 = 8 \qquad \text{(both positive, answer is positive)}

(4)+(6)=10(both negative, answer is negative)(-4) + (-6) = -10 \qquad \text{(both negative, answer is negative)}

Rule: Same signs — add the absolute values, keep the sign.

Case 2: Different Signs

When the numbers have different signs, subtract the smaller absolute value from the larger absolute value, then take the sign of the number with the larger absolute value.

7+(3)=4(|7| > |-3|, answer is positive)7 + (-3) = 4 \qquad \text{(|7| > |-3|, answer is positive)}

(9)+5=4(|-9| > |5|, answer is negative)(-9) + 5 = -4 \qquad \text{(|-9| > |5|, answer is negative)}

Rule: Different signs — subtract the absolute values, take the sign of the larger.

Example 1: Adding Integers

Compute (8)+(5)(-8) + (-5).

Both numbers are negative (same sign).

8+5=8+5=13|-8| + |-5| = 8 + 5 = 13

Keep the negative sign:

(8)+(5)=13(-8) + (-5) = -13

Example 2: Adding Integers with Different Signs

Compute (14)+9(-14) + 9.

The signs are different. Find the absolute values: 14=14|-14| = 14, 9=9|9| = 9.

149=514 - 9 = 5

The number with the larger absolute value is 14-14 (negative), so the answer is negative:

(14)+9=5(-14) + 9 = -5

Subtracting Integers

Subtraction of integers follows one key rule: subtracting a number is the same as adding its opposite (also called its additive inverse).

ab=a+(b)a - b = a + (-b)

This rule converts every subtraction problem into an addition problem, and then you apply the addition rules above.

Example 3: Subtracting a Positive Integer

Compute 3103 - 10.

Rewrite as addition:

310=3+(10)3 - 10 = 3 + (-10)

Different signs: 10>3|{-10}| > |3|, so the answer is negative.

103=7    3+(10)=710 - 3 = 7 \implies 3 + (-10) = -7

Example 4: Subtracting a Negative Integer

Compute (6)(4)(-6) - (-4).

Rewrite: subtracting 4-4 means adding +4+4.

(6)(4)=(6)+4(-6) - (-4) = (-6) + 4

Different signs: 6=6>4=4|-6| = 6 > |4| = 4, answer is negative.

64=2    (6)+4=26 - 4 = 2 \implies (-6) + 4 = -2

The “Keep-Change-Change” Shortcut

Many students memorize this pattern for subtraction:

  1. Keep the first number as is
  2. Change the subtraction sign to addition
  3. Change the sign of the second number (flip it)

Then add using the addition rules.

Multiplying Integers

Multiplication follows simple sign rules:

First FactorSecond FactorProduct
PositivePositivePositive
NegativeNegativePositive
PositiveNegativeNegative
NegativePositiveNegative

Summary:

  • Same signs \rightarrow positive product
  • Different signs \rightarrow negative product

Example 5: Multiplying Integers

Compute (7)×(8)(-7) \times (-8).

Both factors are negative (same sign), so the product is positive:

(7)×(8)=56(-7) \times (-8) = 56

Compute (5)×6(-5) \times 6.

Different signs (negative times positive), so the product is negative:

(5)×6=30(-5) \times 6 = -30

Multiplying More Than Two Integers

When multiplying several integers, count the negative factors:

  • Even number of negative factors \rightarrow positive product
  • Odd number of negative factors \rightarrow negative product

Example 6: Three Factors

Compute (2)×3×(4)(-2) \times 3 \times (-4).

Multiply the absolute values: 2×3×4=242 \times 3 \times 4 = 24.

Count negatives: two negative factors (even), so the product is positive.

(2)×3×(4)=24(-2) \times 3 \times (-4) = 24

Dividing Integers

Division follows the same sign rules as multiplication:

  • Same signs \rightarrow positive quotient
  • Different signs \rightarrow negative quotient

Example 7: Dividing Integers

Compute (36)÷(9)(-36) \div (-9).

Same signs (both negative), so the quotient is positive:

(36)÷(9)=4(-36) \div (-9) = 4

Compute 42÷(7)42 \div (-7).

Different signs, so the quotient is negative:

42÷(7)=642 \div (-7) = -6

Important Note: Division by Zero

Division by zero is undefined — it is not allowed. There is no number that, when multiplied by zero, gives a nonzero result.

Any number÷0=undefined\text{Any number} \div 0 = \text{undefined}

Real-World Application: HVAC — Temperature Changes

An HVAC technician is monitoring a walk-in freezer. At 6:00 AM, the temperature reads 12°-12\degreeF. Over the next two hours, the compressor drops the temperature by 7°7\degreeF. Then a door is left open and the temperature rises 15°15\degreeF.

Step 1: Starting temperature: 12°-12\degreeF

Step 2: Drop by 7°7\degreeF (temperature decreases, so subtract):

127=12+(7)=19°F-12 - 7 = -12 + (-7) = -19\degree\text{F}

Step 3: Rise by 15°15\degreeF (temperature increases, so add):

19+15=4°F-19 + 15 = -4\degree\text{F}

The freezer is at 4°-4\degreeF — still below zero, but warmer than the target of 19°-19\degreeF. The technician knows the door must be shut and the unit needs time to recover.

Real-World Application: Electrician — Voltage Readings

When an electrician tests circuits, voltage readings can be positive or negative depending on the probe orientation. If a multimeter reads 24-24 volts across one component and 24-24 volts across a second identical component in series, the total voltage drop is:

(24)+(24)=48 volts(-24) + (-24) = -48 \text{ volts}

The negative sign simply indicates the direction of the voltage drop relative to the probe placement. Understanding integer addition prevents misreading the total as 00 (a common mistake when someone thinks the negatives “cancel”).

Common Mistakes to Avoid

  1. Confusing subtraction with negative signs. In 5(3)5 - (-3), the first minus is subtraction and the second is the sign of the number. Rewrite as 5+3=85 + 3 = 8.
  2. Forgetting that subtracting a negative means adding. (4)(9)=(4)+9=5(-4) - (-9) = (-4) + 9 = 5, not 13-13.
  3. Getting sign rules backward for multiplication. Two negatives make a positive: (3)×(5)=15(-3) \times (-5) = 15, not 15-15.
  4. Ignoring zero’s special role. 00 times any integer is 00, and 00 divided by any nonzero integer is 00. But dividing by 00 is undefined.
  5. Applying multiplication sign rules to addition. Adding two negatives gives a negative (not positive). The “same sign gives positive” rule only applies to multiplication and division.

Practice Problems

Test your understanding with these problems. Click to reveal each answer.

Problem 1: Compute (15)+8(-15) + 8.

Different signs. 15=15|-15| = 15, 8=8|8| = 8. Subtract: 158=715 - 8 = 7. The larger absolute value is 1515 (negative).

Answer: (15)+8=7(-15) + 8 = -7

Problem 2: Compute (7)(12)(-7) - (-12).

Rewrite: (7)(12)=(7)+12(-7) - (-12) = (-7) + 12.

Different signs. 12>7|12| > |-7|, so the answer is positive. 127=512 - 7 = 5.

Answer: (7)(12)=5(-7) - (-12) = 5

Problem 3: Compute (9)×4(-9) \times 4.

Different signs, so the product is negative. 9×4=369 \times 4 = 36.

Answer: (9)×4=36(-9) \times 4 = -36

Problem 4: Compute (56)÷(8)(-56) \div (-8).

Same signs (both negative), so the quotient is positive. 56÷8=756 \div 8 = 7.

Answer: (56)÷(8)=7(-56) \div (-8) = 7

Problem 5: Compute (3)×(2)×(5)(-3) \times (-2) \times (-5).

Multiply absolute values: 3×2×5=303 \times 2 \times 5 = 30.

Count negative factors: three (odd), so the product is negative.

Answer: (3)×(2)×(5)=30(-3) \times (-2) \times (-5) = -30

Problem 6: A freezer starts at 8°-8\degreeF. The temperature drops 6°6\degreeF, then rises 20°20\degreeF. What is the final temperature?

Start: 8°-8\degreeF.

After dropping 6°6\degree: 86=8+(6)=14°-8 - 6 = -8 + (-6) = -14\degreeF.

After rising 20°20\degree: 14+20=6°-14 + 20 = 6\degreeF.

Answer: The final temperature is 6°6\degreeF.

Problem 7: An electrician measures voltage drops of 12-12 V, 8-8 V, and 4-4 V across three resistors in series. What is the total voltage drop?

(12)+(8)+(4)=24 V(-12) + (-8) + (-4) = -24 \text{ V}

All three are negative (same sign), so add the absolute values (12+8+4=2412 + 8 + 4 = 24) and keep the negative sign.

Answer: The total voltage drop is 24-24 V.

Key Takeaways

  • Integers include all positive whole numbers, their negatives, and zero
  • Adding same signs: add absolute values, keep the sign
  • Adding different signs: subtract absolute values, take the sign of the larger
  • Subtracting is the same as adding the oppositeab=a+(b)a - b = a + (-b)
  • Multiplying/dividing: same signs give a positive result, different signs give a negative result
  • When multiplying multiple integers, count the negative factors — even count means positive, odd count means negative
  • Division by zero is undefined
  • Negative numbers model real-world quantities like temperature drops, debt, below-sea-level elevation, and voltage drops

Return to Pre-Algebra for more topics in this section.

Last updated: March 29, 2026