Arithmetic

Exponents and Square Roots

Last updated: March 2026 · Beginner
Before you start

You should be comfortable with:

An exponent tells you how many times to multiply a number by itself. A square root reverses the process — it asks “what number, multiplied by itself, gives this result?” These two operations are inverses of each other, like multiplication and division.

Exponents

an=a×a×a××an timesa^n = \underbrace{a \times a \times a \times \cdots \times a}_{n \text{ times}}

  • aa is the base — the number being multiplied
  • nn is the exponent (or power) — how many times to multiply

Common Powers

21=222=423=824=1625=322^1 = 2 \qquad 2^2 = 4 \qquad 2^3 = 8 \qquad 2^4 = 16 \qquad 2^5 = 32

31=332=933=2734=813^1 = 3 \qquad 3^2 = 9 \qquad 3^3 = 27 \qquad 3^4 = 81

51=552=2553=1255^1 = 5 \qquad 5^2 = 25 \qquad 5^3 = 125

101=10102=100103=1,000104=10,00010^1 = 10 \qquad 10^2 = 100 \qquad 10^3 = 1{,}000 \qquad 10^4 = 10{,}000

Vocabulary

ExpressionRead asValue
424^2”four squared”16
434^3”four cubed”64
444^4”four to the fourth power”256

“Squared” and “cubed” have special names because they connect to geometry — the area of a square with side 4 is 42=164^2 = 16, and the volume of a cube with side 4 is 43=644^3 = 64.

Special Exponents

a1=a(any number to the first power is itself)a^1 = a \qquad \text{(any number to the first power is itself)}

a0=1(any nonzero number to the zero power is 1)a^0 = 1 \qquad \text{(any nonzero number to the zero power is 1)}

Why is a0=1a^0 = 1? Look at the pattern:

24=16,23=8,22=4,21=2,20=  ?2^4 = 16, \quad 2^3 = 8, \quad 2^2 = 4, \quad 2^1 = 2, \quad 2^0 = \;?

Each step divides by 2, so 20=2÷2=12^0 = 2 \div 2 = 1.

Example 1: Evaluate 535^3

53=5×5×5=25×5=1255^3 = 5 \times 5 \times 5 = 25 \times 5 = 125

Example 2: Evaluate 262^6

26=2×2×2×2×2×2=642^6 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 64

Example 3: Evaluate 10510^5

105=100,00010^5 = 100{,}000

For powers of 10, the exponent equals the number of zeros.

Square Roots

The square root of a number nn is the value that, when multiplied by itself, gives nn:

n=xmeansx2=n\sqrt{n} = x \quad \text{means} \quad x^2 = n

Example 4: 25\sqrt{25}

What number squared equals 25? 5×5=255 \times 5 = 25, so 25=5\sqrt{25} = 5.

Example 5: 144\sqrt{144}

12×12=14412 \times 12 = 144, so 144=12\sqrt{144} = 12.

Perfect Squares

A perfect square is a number whose square root is a whole number. These are worth memorizing:

nnn2n^2nnn2n^2
11981
2410100
3911121
41612144
52513169
63614196
74915225
86420400

Estimating Non-Perfect Square Roots

Most numbers are not perfect squares, so their square roots are not whole numbers. You can estimate by finding the two perfect squares it falls between.

Example 6: Estimate 50\sqrt{50}

72=497^2 = 49 and 82=648^2 = 64, so 50\sqrt{50} is between 7 and 8.

Since 50 is very close to 49, 507.07\sqrt{50} \approx 7.07.

Example 7: Estimate 200\sqrt{200}

142=19614^2 = 196 and 152=22515^2 = 225, so 200\sqrt{200} is between 14 and 15.

200200 is close to 196, so 20014.1\sqrt{200} \approx 14.1.

Cube Roots

A cube root asks “what number cubed gives this result?”

n3=xmeansx3=n\sqrt[3]{n} = x \quad \text{means} \quad x^3 = n

Example 8: 273\sqrt[3]{27}

3×3×3=273 \times 3 \times 3 = 27, so 273=3\sqrt[3]{27} = 3.

Common Cube Roots

nnn3n^3nnn3n^3
115125
286216
327101,000
464

Practice Problems

Test your understanding with these problems. Click to reveal each answer.

Problem 1: Evaluate 343^4

34=3×3×3×3=813^4 = 3 \times 3 \times 3 \times 3 = 81

Problem 2: Evaluate 81\sqrt{81}

9×9=819 \times 9 = 81, so 81=9\sqrt{81} = 9.

Problem 3: What is 707^0?

Any nonzero number to the zero power is 1.

Answer: 70=17^0 = 1

Problem 4: Estimate 75\sqrt{75} to the nearest tenth

82=648^2 = 64 and 92=819^2 = 81. Since 75 is between 64 and 81, 75\sqrt{75} is between 8 and 9.

7575 is closer to 8181 (7564=1175 - 64 = 11, 8175=681 - 75 = 6), so 758.7\sqrt{75} \approx 8.7.

Problem 5: Evaluate 1253\sqrt[3]{125}

5×5×5=1255 \times 5 \times 5 = 125, so 1253=5\sqrt[3]{125} = 5.

Key Takeaways

  • Exponents mean repeated multiplication: an=aa^n = a multiplied by itself nn times
  • Square roots reverse squaring: n\sqrt{n} asks “what squared gives nn?”
  • a0=1a^0 = 1 for any nonzero aa; a1=aa^1 = a always
  • Perfect squares (1, 4, 9, 16, 25, 36, 49, 64, 81, 100…) have whole-number square roots
  • Estimate non-perfect square roots by finding the two nearest perfect squares
  • Cube roots reverse cubing: n3\sqrt[3]{n} asks “what cubed gives nn?”

Return to Arithmetic for more foundational math topics.

Last updated: March 29, 2026